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a)zał. x-3≠0 ∧ x-2≠0
x≠3 ∧ x≠2
__4__ _ __3__=
..x-3.......x-2..
=[4(x-2)-3(x-3)]:(x-3)(x-2)=[4x-8-3x+9]:(x-3)(x-2)=[x+1]:(x-3)(x-2)
b) zał. x²-9≠0
x≠3 ∧ x≠-3
__9__ _ __x³ - 27__=
..x+3.........x²-9....
=[9(x+3)-(x³-27)]:(x²-9)=[9x+27-x³+27]:(x²-9)=[-x³+9x]:(x²-9)