NH4Cl = NH3 + HCl
1mol NH4Cl - 53g
x mola - 40g
x = 0,75mola
1mol NH4Cl - 1mol NH3 - 1mol HCl
1mol - 22,4dm3
0,75 mola - x
x = 16,8dm3
16,8dm3 = 16,8dm3 = 33,6dm3
Oba gazy zajęly objętość okolo 34dm3
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NH4Cl = NH3 + HCl
1mol NH4Cl - 53g
x mola - 40g
x = 0,75mola
1mol NH4Cl - 1mol NH3 - 1mol HCl
1mol - 22,4dm3
0,75 mola - x
x = 16,8dm3
16,8dm3 = 16,8dm3 = 33,6dm3
Oba gazy zajęly objętość okolo 34dm3