Obwód trójkata foremnego jest równy 6√3cm. Pole tego trójkąta wynosi:
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6 √ 3 cm :3 = 2 √ 3 cm
p = ( a ^ 2 * √ 3 ) / 4 = ( ( 2 √ 3 ) ^ 2 * √ 3 ) / 4 = 4 * 3 * √ 3 ) / 4 = 12 √ 3 / 4= 3 √ 3 cm ^ 2
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6 √ 3 cm :3 = 2 √ 3 cm
p = ( a ^ 2 * √ 3 ) / 4 = ( ( 2 √ 3 ) ^ 2 * √ 3 ) / 4 = 4 * 3 * √ 3 ) / 4 = 12 √ 3 / 4= 3 √ 3 cm ^ 2