Obw = 40
a = x
b = 0,5 (40 - 2x)
x + 4 = 0,5 (40 - 2x) - 5
x + 4 = 20 - 1x - 5
x + x = 20 - 5 - 4
2x = 11 | :2
x = 5,5
20 - 5,5 = 14,5
P = ab
P = 5,5 * 14,5
P = 79,75cm^2
x = dł jednego boku 0,5(16-2x) = dł drugiego boku x-1=8-x+1 2x=8 x=4
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x+4=y-5
x+y=20
y=x+9
x+x+9=20
x=5,5
y=14,5
Boki prostokąta to 5,5 i 14,5 a kwadratu to 9,5
Obw = 40
a = x
b = 0,5 (40 - 2x)
x + 4 = 0,5 (40 - 2x) - 5
x + 4 = 20 - 1x - 5
x + x = 20 - 5 - 4
2x = 11 | :2
x = 5,5
20 - 5,5 = 14,5
P = ab
P = 5,5 * 14,5
P = 79,75cm^2
x = dł jednego boku
0,5(16-2x) = dł drugiego boku
x-1=8-x+1
2x=8
x=4
Poproszę o naj ;d