OBLICZCIE MI ODDZIELNIE STOSUNKI WAGOWE BUTANOLU, A POTEM ODDZIELNIE PROPANOLUOK..;)
Butanol- C4H9OH
mC4H9OH- 4*12u+10*1u+16u
Stosunek:
C:H:O
48:10:16
24:5:8
Propanol- C3H7OH
mC3H7OH-3*12u+8*1u+16u
36:8:16
9:2:4
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Butanol- C4H9OH
mC4H9OH- 4*12u+10*1u+16u
Stosunek:
C:H:O
48:10:16
24:5:8
Propanol- C3H7OH
mC3H7OH-3*12u+8*1u+16u
Stosunek:
C:H:O
36:8:16
9:2:4