Oblicz:
a)
b)
c)
* to znak mnożenia
: to znak dzielenia
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a)![(\sqrt{3}-2\sqrt{3}+3\sqrt{3})\cdot \sqrt{3}=2\sqrt{3}\cdot\sqrt{3}=6 (\sqrt{3}-2\sqrt{3}+3\sqrt{3})\cdot \sqrt{3}=2\sqrt{3}\cdot\sqrt{3}=6](https://tex.z-dn.net/?f=%28%5Csqrt%7B3%7D-2%5Csqrt%7B3%7D%2B3%5Csqrt%7B3%7D%29%5Ccdot+%5Csqrt%7B3%7D%3D2%5Csqrt%7B3%7D%5Ccdot%5Csqrt%7B3%7D%3D6+)
b)![\sqrt{45}\cdot\sqrt{5}-^{3}\sqrt{2}\cdot ^{3}\sqrt{4}=\sqrt{225}-^{3}\sqrt{8}=15-2=13 \sqrt{45}\cdot\sqrt{5}-^{3}\sqrt{2}\cdot ^{3}\sqrt{4}=\sqrt{225}-^{3}\sqrt{8}=15-2=13](https://tex.z-dn.net/?f=%5Csqrt%7B45%7D%5Ccdot%5Csqrt%7B5%7D-%5E%7B3%7D%5Csqrt%7B2%7D%5Ccdot+%5E%7B3%7D%5Csqrt%7B4%7D%3D%5Csqrt%7B225%7D-%5E%7B3%7D%5Csqrt%7B8%7D%3D15-2%3D13)
c)![\sqrt{\frac{7}{4}}\cdot \sqrt{\frac{16}{63}}+^{3}\sqrt{125}=\sqrt{\frac{4}{9}}+5=\frac{2}{3}+5=5\frac{2}{3} \sqrt{\frac{7}{4}}\cdot \sqrt{\frac{16}{63}}+^{3}\sqrt{125}=\sqrt{\frac{4}{9}}+5=\frac{2}{3}+5=5\frac{2}{3}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B7%7D%7B4%7D%7D%5Ccdot+%5Csqrt%7B%5Cfrac%7B16%7D%7B63%7D%7D%2B%5E%7B3%7D%5Csqrt%7B125%7D%3D%5Csqrt%7B%5Cfrac%7B4%7D%7B9%7D%7D%2B5%3D%5Cfrac%7B2%7D%7B3%7D%2B5%3D5%5Cfrac%7B2%7D%7B3%7D)