oblicz:
Δ = b² - 4*a*c = 1²- 4*1*(-6) = 1 + 24 = 25
√Δ = 5
x₁ = -b -√Δ /2a = 1-5 / 2 = -4/2 = -2
x₂ = -b +√Δ /2a = 1+5 / 2 = 6/2 = 3
Rozwiązanie:
x ≠ -2
x ≠ 3
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Δ = b² - 4*a*c = 1²- 4*1*(-6) = 1 + 24 = 25
√Δ = 5
x₁ = -b -√Δ /2a = 1-5 / 2 = -4/2 = -2
x₂ = -b +√Δ /2a = 1+5 / 2 = 6/2 = 3
Rozwiązanie:
x ≠ -2
x ≠ 3