oblicz zawartosc procentowa pierwiastkow w kwasie propionowym
C2H5COOH
mC=12u
mH=1u
mO=16u
mC2H5COOH=3*12+6*1+2*16=36+6+32=74
%pierwiastka=(mpierwiastka/mzwiazku)*100%
%c=(36/74)*100%=3600%/74=48,7%
%H=(6/74)*100%=600%/74=8,1%
%O=(32/74)*100%=3200/74=43,2%
mC2H5COOH=36u+6u+32u=74u
%C = (36/74)*100% = 48,6%
%H = (6/74)*100% = 8,2%
%O = (32/74)*100% = 43,2%
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C2H5COOH
mC=12u
mH=1u
mO=16u
mC2H5COOH=3*12+6*1+2*16=36+6+32=74
%pierwiastka=(mpierwiastka/mzwiazku)*100%
%c=(36/74)*100%=3600%/74=48,7%
%H=(6/74)*100%=600%/74=8,1%
%O=(32/74)*100%=3200/74=43,2%
mC2H5COOH=36u+6u+32u=74u
%C = (36/74)*100% = 48,6%
%H = (6/74)*100% = 8,2%
%O = (32/74)*100% = 43,2%