Błędnie podano wzór hydratu
m CaCl₂*6H₂O=40u+2*35,5u+12*1u+6*16u=219u
m 6H₂O=108u
219g hydratu------100%
108g H₂O-----------x%
x = 49,3% H₂O
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Błędnie podano wzór hydratu
m CaCl₂*6H₂O=40u+2*35,5u+12*1u+6*16u=219u
m 6H₂O=108u
219g hydratu------100%
108g H₂O-----------x%
x = 49,3% H₂O