Oblicz zawartość procentową (%masowy) węgla w butanie
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mC=12*4=48[u]
mH=1*10=10[u]
48+10=58[u]
%C=48/58*100%=4800/58%=82.76%
m C4H10=4*mC+10*mH=4*12u+10*1u=48u+10u=58u
mC4=4*12u=48u
58u---100%
48---x%
x=48*100/58=82,76%