Oblicz x, jeżeli:
a)
b)
c)
d)
e)
f)
a) log 1000 = x <=> 10^x = 1000 => x = 3
x = 3
====
b) log 2 ( x) = 10 <=> 2^10 = x => x = 1024
x = 1024
==========
c) log 1/5 ( 1 ) = x <=> (1/5)^x = 1 => x = 0
x = 0
d) log 1/2 ( x) = - 2 <=> (1/2)^ (-2) = x => x = 2^2 = 4
x = 4
e) log x ( 27 ) = 3 <=> x^3 = 27 => x = 3
=======
f) log x ( 36) = - 2 <=> x^(-2) = 36 => x = 1/6
x = 1/6
============
rozwiązanie w załączniku
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a) log 1000 = x <=> 10^x = 1000 => x = 3
x = 3
====
b) log 2 ( x) = 10 <=> 2^10 = x => x = 1024
x = 1024
==========
c) log 1/5 ( 1 ) = x <=> (1/5)^x = 1 => x = 0
x = 0
==========
d) log 1/2 ( x) = - 2 <=> (1/2)^ (-2) = x => x = 2^2 = 4
x = 4
==========
e) log x ( 27 ) = 3 <=> x^3 = 27 => x = 3
x = 3
=======
f) log x ( 36) = - 2 <=> x^(-2) = 36 => x = 1/6
x = 1/6
============
rozwiązanie w załączniku