oblicz wysokosc trapezu ktorego podstawy wynosza 10cm i 6 cm a pole ma 56cm kwadratowych
a=6cm
b=10cm
P=56cm²
h=?
P=½(a+b)h
56=½(6+10)h
56=½*16h
56=8h /:8
7=h
h=7cm
Dane:a = 10cmb = 6cmP = 56cm^2Szukane:h = ?P = 1/2h(a+b)56 = 1/2(10+6)*h56 = 8*hh = 56/:8h = 7[cm]Odp: Wysokość trapezu wynosi 7cm.
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a=6cm
b=10cm
P=56cm²
h=?
P=½(a+b)h
56=½(6+10)h
56=½*16h
56=8h /:8
7=h
h=7cm
Dane:
a = 10cm
b = 6cm
P = 56cm^2
Szukane:
h = ?
P = 1/2h(a+b)
56 = 1/2(10+6)*h
56 = 8*h
h = 56/:8
h = 7[cm]
Odp: Wysokość trapezu wynosi 7cm.