Oblicz wysokość rombu, którego przekątne mają 12 cm i 16 cm a bok ma 10 cm
d1 = 12cm
d2 = 16cm
P = 1/2 * d1 * d2
P = `1/2 * 12 * 16
P = 96cm^2
P = a * h
96 = 10 * h
96 : 10 = h
h = 9,6cm ---------- odpowiedź
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d1 = 12cm
d2 = 16cm
P = 1/2 * d1 * d2
P = `1/2 * 12 * 16
P = 96cm^2
P = a * h
96 = 10 * h
96 : 10 = h
h = 9,6cm ---------- odpowiedź