Question

oblicz wartości pozostałych funkcji trygonometrycznych,jeśli :

a) tg a=

b) sin a=

c)cos a =

Answer 1

tga=5/12 = a/b

czyli ctga =12/5 = b/a

a=5, b=12

c²=a²+b² = 25+144 =169

c=13

sina = a/c = 5/13

cosa=b/c= 12/13

 

sina = a/c=1/3

a=1

c=3

b²=c²-a²=9-1=8

b=√8 = 2√2

cosa = b/c= (2√2)/3

tga = a/b = 1/2√2 = √2/4

ctga = b/a = 2√2

 

cosa = b/c=1/2

b=1

c=2

a²=4-1=√3

sina=√3/2

tga=√3

ctga=1/√3= √3/3