OBLICZ WARTOŚC WYRAZENIA I(½)³ - (1,5)² * 4²I + 2⁻² - I-3²* 3⁵: 3⁶I
To jest na ocene!! Prosze pomóżcie dam najj ;)
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znak [ i ] to wartość bezwzględna, nie mogłam użyć innego znaku
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=![[\frac{1}{8}-(\frac{3}{2})^2*16]+(\frac{1}{2})^2-[-3^{2+5-6}]=[\frac{1}{8}-\frac{9}{4}*16]+\frac{1}{4}-[-3^1]= [\frac{1}{8}-(\frac{3}{2})^2*16]+(\frac{1}{2})^2-[-3^{2+5-6}]=[\frac{1}{8}-\frac{9}{4}*16]+\frac{1}{4}-[-3^1]=](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7B8%7D-%28%5Cfrac%7B3%7D%7B2%7D%29%5E2%2A16%5D%2B%28%5Cfrac%7B1%7D%7B2%7D%29%5E2-%5B-3%5E%7B2%2B5-6%7D%5D%3D%5B%5Cfrac%7B1%7D%7B8%7D-%5Cfrac%7B9%7D%7B4%7D%2A16%5D%2B%5Cfrac%7B1%7D%7B4%7D-%5B-3%5E1%5D%3D)
=![[\frac{1}{8}-36]+\frac{1}{4}-3=35\frac{7}{8}-2\frac{3}{4}=33\frac{1}{8} [\frac{1}{8}-36]+\frac{1}{4}-3=35\frac{7}{8}-2\frac{3}{4}=33\frac{1}{8}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7B8%7D-36%5D%2B%5Cfrac%7B1%7D%7B4%7D-3%3D35%5Cfrac%7B7%7D%7B8%7D-2%5Cfrac%7B3%7D%7B4%7D%3D33%5Cfrac%7B1%7D%7B8%7D)
znak [ i ] to wartość bezwzględna, nie mogłam użyć innego znaku