Oblicz wartość wyrażenia 2a³-4a²b+1 dla :
a) a=1 i b= -2
b) a= -0.5 i b= 3
c) a=4 i b = 0
d) a= jedna trzecia b= -3
proszę o pomoc ! do godziny 21
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a)
2* 1^{3}-4*1^{2} * (-2)+1
2*3-4*1*(-2)+1
6-4*(-2)+1
6-8+1= -1
b)
2* -0,5^{3} -4* -0,5^{2}
2* (-0125) - 4* 0,25*3+1
-0,25-3+1= -2,25
c)
2* 4^{3}-4* 4^{2}*0+1
2*64-4*16*0+1
128- 0+1=129
d)
2* \frac{1}{3}^3 - 4* \frac{1}{3}^2 * (-3) +1
2* \frac{1}{27} - 4* \frac{1}{9}* (-3)+1
\frac{2}{27}- \frac{4}{9}* (-3) +1
\frac{2}{27}- \frac{12}{9}+ 1
\frac{2}{27}- \frac{36}{27}+1=-\frac{34}{27}+1= \frac{1}{7}