" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
l=a
r=½a
h=a√3:2
pole podstawy=π×(½a)²=¼a²π
v=⅓×¼a²π×a√3:2=¹/₂₄ a³√3π j.³
pole=π×½a(a+½a)=¾a²π j.²
b] powstaną 2 złaczone podstawami stożki o :
r= a√3:2
h=½a
pole=2πrl=2π×a√3:2×a=a²√3π j,²
v=(⅓π(a√3/2)²×½a)×2=a³×¼π=¼a³πj.³