oblicz sume szesciu wyrazów malejacego ciagu geometrycznego, gdy
a5=8 a7=2
a₅ *q²=a₇
8*q²=2 | :8
q²=2/8=¼
q=½
S₆=?
a₁*q*q*q*q=a₅
a₁*q⁴=8
a₁*(½)⁴=8
a₁* 1/16 =8
a₁= 16*8=128
S₆=a₁ * (1-q⁶)/(1-q)
S₆=128 * ( 1-1/64)/½
S₆=128 * 63/64 * 2
S₆=4*65
S₆=252
Pozdrawiam,
Kluuuska (;
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a₅ *q²=a₇
8*q²=2 | :8
q²=2/8=¼
q=½
S₆=?
a₁*q*q*q*q=a₅
a₁*q⁴=8
a₁*(½)⁴=8
a₁* 1/16 =8
a₁= 16*8=128
S₆=a₁ * (1-q⁶)/(1-q)
S₆=128 * ( 1-1/64)/½
S₆=128 * 63/64 * 2
S₆=4*65
S₆=252
Pozdrawiam,
Kluuuska (;