Oblicz stosunek masy węgla do masy wodoru oraz do masy tlenu w sacharozie
masa C12H22O11 = 12*12u + 22 *1u + 11*16u = 144u+22u+176u = 342uC:H:O = 144:22:176 = 72:11:88
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masa C12H22O11 = 12*12u + 22 *1u + 11*16u = 144u+22u+176u = 342u
C:H:O = 144:22:176 = 72:11:88