Oblicz skład procentowy siarczanu 6 potasu,K2SO4
mK2SO4=78u+32u+64u=174u
%K = (78/174)*100% = 44,8%
%S = (32/174)*100% = 18,4%
%O = (64/174)*100% = 36,8%
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mK2SO4=78u+32u+64u=174u
%K = (78/174)*100% = 44,8%
%S = (32/174)*100% = 18,4%
%O = (64/174)*100% = 36,8%