Oblicz skład procentowy butanu.
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Masa: 4 * 12u + 10 * 1u = 58u
Węgiel:
4 * 12u = 48u
58u ---- 100%
48u ---- x %
x = (48u * 100%) : 58u ≈ 82,76%
Wodór:
10 * 1u = 10u
58u --- 100%
10u --- x %
x = (10u * 100%) : 58u ≈ 17,24%
mC= 12u
mH= 1u
C4H10= (12*4) + (1u*10) = 48u +10u= 58u
(48u * 100%) : 58u= 82,75 %