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Al(OH)3 - wodorotlenek glinu
mAl(OH)3 = 27u+3*(1u+16u) = 78u
Al : 3O " 3H = 27:48:3 = 9:16:1
%Al = 27u/78u * 100% = 35%
%O = 48u/78u * 100% = 62%
%H = 100% - (35%+62%) = 3%
%Al=27u*100%/78u=34,6%
%O=16u*3*100%/78u=61,5%
%H=3u*100%/78u=3,9%
mAl : mO : mH
27 : 48 : 3 /:3
9 : 16 : 1