Oblicz pole trójkąta równoramiennego o bokach 6,6,10
p=1/2a*h
h=pierwiastek z (b^2-1/4a^2)
a=10
b=6
h= pierw z (36-1/4*100)= pierw z (36-25)=pierw z 11=v11
p=1/2*10*v11=5v11 (5 pierwiastek z 11)
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p=1/2a*h
h=pierwiastek z (b^2-1/4a^2)
a=10
b=6
h= pierw z (36-1/4*100)= pierw z (36-25)=pierw z 11=v11
p=1/2*10*v11=5v11 (5 pierwiastek z 11)