oblicz pole szesianu,w ktory krawedz ma dlugosc : a.7cm b.1dm
Pc= 6a²
a- bok
a) Pc= 6*(7cm)²
Pc= 294 cm²
b) Pc=6*(1dm)²
Pc= 6 dm²
Liczę na naj :)
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Pc= 6a²
a- bok
a) Pc= 6*(7cm)²
Pc= 294 cm²
b) Pc=6*(1dm)²
Pc= 6 dm²
Liczę na naj :)