Oblicz pole rombu o boku dlugosci 10 cm i kacie ostrym 60'
a = 10 cmα = 60⁰Mamyb = h√2 ----> h = b /√2 = 8 /√2 cm = 4√2 cmP = a*h = 10 cm * 4√2 cm = 40√2 cm²
a = 10cm
α = 60°
P = a²·sinα
P= 100·sin60°
P=100·√3/2
P=50√3 (cm²)
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a = 10 cm
α = 60⁰
Mamy
b = h√2 ----> h = b /√2 = 8 /√2 cm = 4√2 cm
P = a*h = 10 cm * 4√2 cm = 40√2 cm²
a = 10cm
α = 60°
P = a²·sinα
P= 100·sin60°
P=100·√3/2
P=50√3 (cm²)