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Pp = 2 * 1/2 * 12 cm * 16 cm
Pp = 192 cm²
16:2=8
12:2=6
Nalezy skorzystać z twierdzenia Pitagorasa, alby obliczyć bok rombu.
x² = 8²+6²
x²=64 + 36
x =√100
x=10
Pb = 4 * 20 cm * 10 cm
Pb = 800 cm²
Pc = 192 cm² + 800cm²
Pc = 992 cm²
Pp=(12*16)/2
Pp=96
x² = 8²+6²
x²=64 + 36
x =√100
x=10
Pb = 4 * 20* 10
Pb = 800
Ppc = 192 + 800
Ppc = 992
d2=16cm
H=20cm
Pc= 2*d1*d2/2+4a*H
(1/2d2)do kwad+(1/2d2)do kwad = a do kwad
8 do kwad+ 6 do kwad = a do kwad
a do kwad=64+36
a do kwad= 100
a=10 cm
Pc= 2*d1*d2/2+4a*H
Pc= 12*16+ 4 *10*20
Pc=192+800
Pc=992 cm kwad