Oblicz pole powierzchni całkowitej i objętosć :
a )szcześcianu o krawedzi 0,5 m
b)prostopadłościanu o wymiarach 1m ,1,5 m,2 m
Proszę o szybką odpowiedź .; ]]
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1.
Pc = ?
Pb = a * a
a = 0,5 m
Pb =![0,25m^{2} 0,25m^{2}](https://tex.z-dn.net/?f=0%2C25m%5E%7B2%7D)
Pc = 4 * Pb + 2 * Pp
Pp = Pb
Pc = 4 * 0,25m + 2 * 0,25m =![6m^{2} 6m^{2}](https://tex.z-dn.net/?f=6m%5E%7B2%7D)
V = a * a * H
V = 0,5m * 0,5m * 0,5m =![0,125m^{3} 0,125m^{3}](https://tex.z-dn.net/?f=0%2C125m%5E%7B3%7D)
2.
Pc = ?
Pb = 2 * (2m * 1,5m) + 2 * (2m * 1m)
=
+ 2 *
=
+
=
Pp = 2 * (1,5m * 1m) = 2 * 1,5m =![3m^{2} 3m^{2}](https://tex.z-dn.net/?f=3m%5E%7B2%7D)
Pc = Pp + Pb
Pc =
+ 10 m2 = ![13m^{2} 13m^{2}](https://tex.z-dn.net/?f=13m%5E%7B2%7D)
V = a * b * H
V = 1m * 1,5m * 2m =![3m^{3} 3m^{3}](https://tex.z-dn.net/?f=3m%5E%7B3%7D)
H - wysokość
Pp - pole podstaw
Pb - pole boczne
Pc - pole całkowite
V - objetość
a / b - boki