zad.10/20 - matematyka 2001 Rozwiąż układ równań metodą postawiania.
b)
4x-3y=2
-2x+y=4
c)
2x+y=3
x-2y=4
:)
y=2x+4
4x-3(2x+4)=2
4x-6x-12-2=0
-2x-14=0
-2x=14/:(-2)
x=-7
-28-3y=2
-3y=28+2
-3y=30/:(-3)
y=-10
y=-2x+3
x-2(-2x+3)=3
x+4x-6-3=0
5x-9=0
5x=9/:5
x=9/5
9/5-2y=4
-2y=-9/5+4
-2y=-9/5+20/5
-2y=11/5/:(-2)
y=-4 2/5
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b)
4x-3y=2
-2x+y=4
y=2x+4
4x-3(2x+4)=2
4x-6x-12-2=0
-2x-14=0
-2x=14/:(-2)
x=-7
-28-3y=2
-3y=28+2
-3y=30/:(-3)
y=-10
c)
2x+y=3
x-2y=4
y=-2x+3
x-2(-2x+3)=3
x+4x-6-3=0
5x-9=0
5x=9/:5
x=9/5
9/5-2y=4
-2y=-9/5+4
-2y=-9/5+20/5
-2y=11/5/:(-2)
y=-4 2/5