Oblicz pole kwadratu o boku 2a+3
P=(2a+3)²
P=(2a+3)·(2a+3)
P=4a²+6a+6a+9
P=4a²+12a+9
(2a+3)*(2a+3)=4a²+6a+6a+9=(4a²+12a+9)j²
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
P=(2a+3)²
P=(2a+3)·(2a+3)
P=4a²+6a+6a+9
P=4a²+12a+9
(2a+3)*(2a+3)=4a²+6a+6a+9=(4a²+12a+9)j²