Oblicz pole koła o obwodzie a)12π cm b)1,2π cm. c)0,8π cm.
O=2πr
a)12πcm=2πr /:π
12cm=2r /:2
r=6cm
P=πr²
P=π*6²
P=36πcm²
b)1,2πcm=2πr /:π
1,2cm=2r /:2
r=0,6cm
P=π*(0,6)²
P=0,36πcm²
c)0,8πcm=2πr /:π
0,8cm=2r /:2
r=0,4cm
P=π*(0,4)²
P=0,16πcm²
a) P-
l = 12\pi cm
r-
r=
P=
b) l = 1,2 cm
r =
P= cm^{2}[\tex]
c) l= cm
P= cm^{2}
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O=2πr
a)12πcm=2πr /:π
12cm=2r /:2
r=6cm
P=πr²
P=π*6²
P=36πcm²
b)1,2πcm=2πr /:π
1,2cm=2r /:2
r=0,6cm
P=π*(0,6)²
P=0,36πcm²
c)0,8πcm=2πr /:π
0,8cm=2r /:2
r=0,4cm
P=π*(0,4)²
P=0,16πcm²
a) P-
l = 12\pi cm
r-
r=
P=
b) l = 1,2 cm
r-
r =
P= cm^{2}[\tex]
c) l= cm
r-
r=
P= cm^{2}