Oblicz pole koła, którego obwód jest równy 39,56 cm .
Ob=2πr
π=3,14
2*3,14*r=39,56
6,28r=39,56/:6,28
r=6,3 cm
P=πr²
P=3,14*(6,3)²
P=3,14* 39,69
P=124,63 cm²
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Ob=2πr
π=3,14
2*3,14*r=39,56
6,28r=39,56/:6,28
r=6,3 cm
P=πr²
P=3,14*(6,3)²
P=3,14* 39,69
P=124,63 cm²