Question

Oblicz pole i obwód trójkąta ABC.

Answer 1

(DB)^2=6^2-4^2

(DB)^2=36-16

(DB)^2=20

(DB)^2=4*5

DB=2V5

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(AC)^2=6^2+4^2

(AC)^2=36+16

(AC)^2=52

(AC)^2=4*13

AC=2V13

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AB=6+2V5=2(3+V5)

P=1/2AB*CD

P=1/2* 2(3+V5)*4

P=4(3+V5)[j^2]

O=2V13+6+2(3+V5)=2(V13+6+3+V5)

O=2(9+V13+V5)[j]