Oblicz pole i obwód prostokąta, którego przekątna o dł. 10 tworzy z jednym z boków kąt o mierze 30 stopni.
P = a*b
obw=2a + 2b
= 30 stopni
d = 10
sin30= i sin30=
=
2a=d
2a=10
a=5
a + b = d
25 + b = 100
b = 75
b =
b = 5
P = 5*5 = 25
obw = 2*5 + 2*5 = 10 + 10
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P = a*b
obw=2a + 2b
= 30 stopni
d = 10
sin30= i sin30=
=
2a=d
2a=10
a=5
a + b = d
25 + b = 100
b = 75
b =
b = 5
P = 5*5 = 25
obw = 2*5 + 2*5 = 10 + 10