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a = bok
pole trojkata = (a × a √3) ÷ 4 (10 × 10 √3 ) ÷ 4 = 25√3
Pc = Pp × h Pc = 25√3 × 10 = 250√3
b)
pole szesciokata = ((a × a √3) ÷ 4 ) × 6 = ((10 × 10 √3 ) ÷ 4 ) × 6 = 150√3
Pc = 150√3 × 10 = 1500√3
c)
P = ((a × a √3) ÷ 4 ) × 8 p = 200√3
Pc = 200√3 × 10 = 2000√3