" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
y' = (1/2√x) · (3+x) - (2+√x)·1 / (3+x)²
y' = 3+x/2√x - (2+√x) / (3+x)²
y' = 3+x - (2+√x)2√x / (3+x)² · 2√x
y' = 3+x - 4√x + 2x / ...
y' = 3+3x - 4√x / ...
b) y' = (sinx-cosx)' · (sinx+cosx) - (sinx-cosx) · (sinx+cosx)' / (sinx+cosx)²
y' = (cosx + sinx)(six + cosx) - (sinx-cosx)(cosx-sinx) / (sinx+cosx)²
y' = (cosx+sinx)² +(sinx-cosx)² / (sinx+cosx)²
y' = 1 + (sinx-cosx)²/(sinx+cosx)²