March 2019 0 48 Report
Oblicz obwód trójkąta o bokach długości:
a=[(1 \frac{1}{3})^{-1}-2^{-2}]^{-3}
b=(7 ^{-3}:7^{-2)}*( \frac{1}{7}) ^{-2}
c= \frac{ \frac{2}{3}^{-2}+(-4)^{-1} }{1^{-1}+2^{-2} }
More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.