October 2018 2 92 Report

Oblicz Pc prawidłowego czworokątnego ostrosłupa o krawędzi podstawy 8cm i wysokości ściany bocznej 12 cm.

Pc=Pp+Pb

Pp=a*a

Pp=4cm*4cm-16cm2

Pb= 1/2 * a * Hb = 1/2 * 8 = 16cm2

Pb=16cm2*4=64cm2

Pb= ------------------------------- (nie wiem co tu_

Pb= ------------------------------- (nie wiem co tu_

Pb= ------------------------------- (nie wiem co tu_

+-------------------------------------- (tu też nie wiem)


More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.