October 2018 2 90 Report

Oblicz Pc prawidłowego czworokątnego ostrosłupa o krawędzi podstawy 8cm i wysokości ściany bocznej 12 cm.

Pc=Pp+Pb

Pp=a*a

Pp=4cm*4cm-16cm2

Pb= 1/2 * a * Hb = 1/2 * 8 = 16cm2

Pb=16cm2*4=64cm2

Pb= ------------------------------- (nie wiem co tu_

Pb= ------------------------------- (nie wiem co tu_

Pb= ------------------------------- (nie wiem co tu_

+-------------------------------------- (tu też nie wiem)


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