Oblicz obwód trójkata A=(0,0) B=(8,6) C=(_6, 2) i znajdź środek okręgu
|AB|=√(8-0)²+(6-0)²= √64+36=√100=10
|BC|=√(6-8)²+(2-6)²= √4+16=√25=5
|AC|=√(6-0)²+(2-0)²=√40=2√10
Obw=10+5+2√10=15+2√10
S=(4,3)
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|AB|=√(8-0)²+(6-0)²= √64+36=√100=10
|BC|=√(6-8)²+(2-6)²= √4+16=√25=5
|AC|=√(6-0)²+(2-0)²=√40=2√10
Obw=10+5+2√10=15+2√10
S=(4,3)