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e = 16cm
f = 12cm
a = ???
b = ???
(Pitagoras)
a^2 = (1/2e)^2 + (1/2)f^2
a^2 = 8^2 + 6^2
a^2 = 64 + 36
a = √100
a = 10cm
b^2 = 100
b = 10cm (takie same obliczenia jak w "a")
L = 2a + 2b
L = 20 + 20
L = 40cm
Odp: Obwód tego rombu wynosi 40cm.
12*12 + 16*16=a*a
144+256=a*a
400=a*a
a= 20
Obwód : 20*4=80
Odpowiedź: Obwód rombu wynosi 80 cm.