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Reakcja spalania propynu:
60g X(dm3)-- piszemy to nad tlenem
C3H4+4O2→3CO2+2H2O
40g 4*22,4dm3--- piszemy to pod tlenem
Układamy proporcję:
60g X
----- = ------
40g 4*22,4dm3
60g*4*22,4dm3
X=---------------------- = 134,4dm3
40g