Oblicz objętość sześcianu o krawędzi 2 k+2
a = 2k+2
V = a³
V = (2k+2)³ = (2k)³+3·(2k)²·2+3·2k·2²+2³ = 8k³+24k²+24k+8
(a+b)³ = a³+3a²b+3ab²+b³
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a = 2k+2
V = a³
V = (2k+2)³ = (2k)³+3·(2k)²·2+3·2k·2²+2³ = 8k³+24k²+24k+8
(a+b)³ = a³+3a²b+3ab²+b³