Oblicz objetosc stożka o wysokości h i promieniu podstawy r jeżeli a) h=5cm,r=3cm
b) h=11 cm, r=6cm
c) h=9cm,r=5cm
a)Pp=*r²
Pp=*3²=3,14*9=28,26
Pc=1/3*28,26*5= 47,1
b)Pp=3,14*6²=3,14*36=113,4
Pc=1/3*113,3*11=415,8
c)Pp=3,14*5=15,7
Pc=1/3*15,7*9=15*3=45
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a)Pp=*r²
Pp=*3²=3,14*9=28,26
Pc=1/3*28,26*5= 47,1
b)Pp=3,14*6²=3,14*36=113,4
Pc=1/3*113,3*11=415,8
c)Pp=3,14*5=15,7
Pc=1/3*15,7*9=15*3=45