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H = 137 m
a = 230 m
Pp = a²√3 / 4
Pp = (230m)² √3 / 4
Pp = 52900m²√3 / 4
Pp = 13225√3 m²
V = 13225√3m²*137m / 3
V = 1811825√3m³ / 4
V = 452956,25 √3 m³
a=230m
V=Pph/3
Pp=a^2
V=230^2*137/3
V=52900*137/3
V=7244300/3
V=2415766,(6)m^3
Objętość piramidy cheopsa wynosi około 2415767 metrów sześciennych.