a = 5 cm
h = 8 cm
V = (1/3) Pp*h = (1/3) a^2 * h = ( 1/3)*( 5 cm)^2 * 8 cm = (1/3)* 25 cm^2 * 8 cm =
= (1/3)* 200 cm^3 = ( 200 / 3) cm^3 = 66 2/3 cm^3
=========================================
Pole powierzchni
Pc = Pp+ Pb = a^2 + 4*(1/2)*a*h1= a^2 + 2a*h1
-----------------------------------------------------------------
d = a p(2) = 5 p(2) cm
x = (1/2) d = 2,5 p(2) cm
b - długośc krawędzi bocznej ostrosłupa
Z tw. Pitagorasa mamy
x^2 + h^2 = b^2
b^2 = [ 2,5 p(2)]^2 + 8^2 = 6,25*2 + 64 = 12,5 + 64 = 76,5
h1 - wysokośc ściany bocznej
[ 0,5 a]^2 + h1^2 = b^2
2,5^2 + h1^2 = 76,5
h1^2 = 76,5 - 6,25 = 70,25 = 281/4
h1 = p(281) / 2
------------------------
zatem
Pc = 5^2 + 2*5* p(281)/2 = 25 + 5 p(281) = 5*[ 5 + p(281)]
Odp. Pc = 5*[ 5 + p(281) ] cm^2
=============================
p(81) - pierwiastek kwadratowy z 281
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a = 5 cm
h = 8 cm
V = (1/3) Pp*h = (1/3) a^2 * h = ( 1/3)*( 5 cm)^2 * 8 cm = (1/3)* 25 cm^2 * 8 cm =
= (1/3)* 200 cm^3 = ( 200 / 3) cm^3 = 66 2/3 cm^3
=========================================
Pole powierzchni
Pc = Pp+ Pb = a^2 + 4*(1/2)*a*h1= a^2 + 2a*h1
-----------------------------------------------------------------
d = a p(2) = 5 p(2) cm
x = (1/2) d = 2,5 p(2) cm
b - długośc krawędzi bocznej ostrosłupa
Z tw. Pitagorasa mamy
x^2 + h^2 = b^2
b^2 = [ 2,5 p(2)]^2 + 8^2 = 6,25*2 + 64 = 12,5 + 64 = 76,5
h1 - wysokośc ściany bocznej
Z tw. Pitagorasa mamy
[ 0,5 a]^2 + h1^2 = b^2
2,5^2 + h1^2 = 76,5
h1^2 = 76,5 - 6,25 = 70,25 = 281/4
h1 = p(281) / 2
------------------------
zatem
Pc = 5^2 + 2*5* p(281)/2 = 25 + 5 p(281) = 5*[ 5 + p(281)]
Odp. Pc = 5*[ 5 + p(281) ] cm^2
=============================
p(81) - pierwiastek kwadratowy z 281