oblicz masy czasteczkowe pierwszych pieciu alkoholi i kwasów.Prosze o pomoc!
ALKOHOLE:
metanol
m.cz.CH3OH = 12u + 4*1u + 16u=32u
etanol
m.cz.C2H5OH= 2*12u + 6*1u + 16u=46u
propanol
m.cz.C3H7OH= 3*12u + 8*1u + 16u= 60u
butanol
m.cz.C4H9OH=4*12u + 10*1u+16u=74u
pentanol
m.cz.C5H11OH=5*12u+12*1u+16u=88u
kw. metanowy
m.cz.HCOOH=12u+2*1u+2*16u=46u
kw. etanowy
m.cz.CH3COOH=2*12u+4*1u+2*16u=60u
kw. propanowy
m.cz.C2H5COOH=3*12u+6*1u+2*16u=74u
kw. butanowy
m.cz.C3H7COOH=4*12u+8*1u+2*16u=88u
kwpentanowy
m.cz.C4H9COOH=5*12u+10*1u+2*16u=102u
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ALKOHOLE:
metanol
m.cz.CH3OH = 12u + 4*1u + 16u=32u
etanol
m.cz.C2H5OH= 2*12u + 6*1u + 16u=46u
propanol
m.cz.C3H7OH= 3*12u + 8*1u + 16u= 60u
butanol
m.cz.C4H9OH=4*12u + 10*1u+16u=74u
pentanol
m.cz.C5H11OH=5*12u+12*1u+16u=88u
kw. metanowy
m.cz.HCOOH=12u+2*1u+2*16u=46u
kw. etanowy
m.cz.CH3COOH=2*12u+4*1u+2*16u=60u
kw. propanowy
m.cz.C2H5COOH=3*12u+6*1u+2*16u=74u
kw. butanowy
m.cz.C3H7COOH=4*12u+8*1u+2*16u=88u
kwpentanowy
m.cz.C4H9COOH=5*12u+10*1u+2*16u=102u