oblicz mase wodoru który potrzebny jest do syntezy amoniaku jesli uzyto 5 moli azotu
M NH3=17 g/mol
nN=5 mol
1 mol NH3 -------1 mol N
x------------------5 mol
x=5 mol NH3
1 mol NH3-------3 mol H
5 mol NH3------- y
y=15mol
Mh=1 g/mol
m=n*Mh
m=15 mol*1 g/mol=15 g
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M NH3=17 g/mol
nN=5 mol
1 mol NH3 -------1 mol N
x------------------5 mol
x=5 mol NH3
1 mol NH3-------3 mol H
5 mol NH3------- y
y=15mol
Mh=1 g/mol
m=n*Mh
m=15 mol*1 g/mol=15 g