Question

Oblicz masę cząsteczkową PROPANU, PROPENU I PROPYNU oraz procentową zawartość węgla w każdym z nich.

Answer 1

dla propanu C₃H₈

 

m = 3 x 12u + 8 x 1u = 44u

m C = 36u

% = 36u/44u x 100% = 81,8%

 

dla propenu C₃H₆

 

m = 3 x 12u + 6 x 1u = 42u

m C= 36u

% = 36u/42u x 100% = 85,7%

 

dla propynu C₃H₄

 

m = 3 x 12u + 4 x 1u = 40u

m C = 36u

% = 36u/40u x 100% = 90%

 

 

 

 

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Litterarum radices amarae sunt, fructus iucundiores

 

Pozdrawiam :)

Answer 2

C3H8 - propan

C3H6- propen

C3H4 propyn

 

C-12u

H-1u

 

C3H8=44u

C3H6=42u

C3H4=40u

 

%C 36/44=81%  propan

%C 36/42=85%  propen

%C 36/40=90% propyn