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log₂3*log₃4 = log₂(3^(log₃4)) = log₂4 = 2
I sposób (zmiana podstawy logarytmu): log(a)b = log(c)b / log(c)a :
log₂3*log₃4 = log₂3 * log₂4 / log₂3 = log₂4 = 2