Oblicz, ile moli dwutlenku węgla powstanie w reakcji spalania 30g etenu w tlenie.
mC2H4=28
C2H4 + 3 O2---->2CO2 + 2H2O
28g etenu-------2mole CO2
30g etenu----------xmoli CO2
x = 2,14mola CO2
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mC2H4=28
C2H4 + 3 O2---->2CO2 + 2H2O
28g etenu-------2mole CO2
30g etenu----------xmoli CO2
x = 2,14mola CO2