Question

oblicz ile gramow tlenku wegla IV zostanie wyemitowane do atmosfery podczas spalania 10kg metanu.

wynik powienien wyjsc 27500g

prosze o obliczenia!!!!

Answer 1

CH4 + 2O2 ----> CO2 + 2H2O                            Mch4=16g/mol
                                                                      Mco2=44g/mol
16g---------------44g
10000g----------x[g]
x=(10000*44)/16
x=27500gCO2

Answer 2

CH₄ + 2O₂ -----> CO₂ + 2H₂O

MCH₄=12g/mol+4*1g/mol=12g/mol+4g/mol=16g/mol

MCO₂=12g/mol+2*16g/mol=12g/mol+32g/mol=44g/mol

10kg=1000dag=10000g

 

16g CH₄ - 44g CO₂

10000g CH₄ - xg CO₂

 

x=(10000g*44g):16g=27500g CO₂